[C++/Python] 백준 13015 - 별찍기 - 23

문제 링크

https://www.acmicpc.net/problem/13015

13015번: 별 찍기 - 23

 

구현 코드

 

	#include <iostream>
	using namespace std;
	void draw_first_and_last(int n, int a){
	for(int i=1;i<=n*2+a;i++){
	if(i <= n || i > n+a)
	cout << '*';
	else
	cout << ' ';
	}
	cout << endl;
	}
	void draw_stars(int n){
	for(int i=0;i<n;i++)
	cout << '*';
	}
	void draw_space(int n){
	for(int i=0;i<n;i++)
	cout << ' ';
	}
	int main(){
	int n;
	cin >> n;
	int a = n * 2 - 3;
	draw_first_and_last(n, a);
	for(int i=1;i<n;i++){
	draw_space(i);
	draw_stars(1);
	draw_space(n-2);
	draw_stars(1);
	if(i != n-1){
	draw_space(a-(i*2));
	draw_stars(1);
	}
	draw_space(n-2);
	draw_stars(1);
	cout << endl;
	}
	for(int i=n-2;i>=1;i--){
	draw_space(i);
	draw_stars(1);
	draw_space(n-2);
	draw_stars(1);
	draw_space(a-(i*2));
	draw_stars(1);
	draw_space(n-2);
	draw_stars(1);
	cout << endl;
	}
	draw_first_and_last(n, a);
	return 0;
	}

view raw 13015.cpp hosted with ❤ by GitHub

	def draw_first_and_last(n, a):
	for i in range(1, n*2+a+1):
	if i <= n or i > n+a:
	print('*', end="")
	else:
	print(' ', end="")
	print("")
	def draw_star(n):
	print('*'*n, end="")
	def draw_space(n):
	print(' '*n, end="")
	n = int(input())
	a = n * 2 - 3
	draw_first_and_last(n,a)
	for i in range(1,n):
	draw_space(i)
	draw_star(1)
	draw_space(n-2)
	draw_star(1)
	if i != n-1:
	draw_space(a-(i*2))
	draw_star(1)
	draw_space(n-2)
	draw_star(1)
	print("")
	for i in range(n-2,0,-1):
	draw_space(i)
	draw_star(1)
	draw_space(n-2)
	draw_star(1)
	draw_space(a-(i*2))
	draw_star(1)
	draw_space(n-2)
	draw_star(1)
	print("")
	draw_first_and_last(n,a)

view raw 13015.py hosted with ❤ by GitHub